Y=0.01x^2+0.7x+6

Solution for Y=0.01x^2+0.7x+6 equation:

=0.01Y^2+0.7Y+6

We move all terms to the left:

-(0.01Y^2+0.7Y+6)=0

We get rid of parentheses

-0.01Y^2-0.7Y-6=0

a = -0.01; b = -0.7; c = -6;
Δ = b2-4ac
Δ = -0.72-4·(-0.01)·(-6)
Δ = 0.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.7)-\sqrt{0.25}}{2*-0.01}=\frac{0.7-\sqrt{0.25}}{-0.02}
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.7)+\sqrt{0.25}}{2*-0.01}=\frac{0.7+\sqrt{0.25}}{-0.02}
$